LessonWhat electricity is · 15 min

Resistance, open circuits and short circuits

The same battery pushes a tiny current through a long thin wire and a huge one through a short thick bar. What sets the difference is resistance: how strongly a path opposes current. It is measured in ohms (Ω).

What makes resistance

Free electrons moving through a metal keep bumping into the vibrating atoms, losing energy as heat. More bumping means more resistance. Four things set it:

  • Material - its resistivity ρ (rho). Copper: 1.68 × 10−8 Ω·m. Nichrome, made for heaters: 1.1 × 10−6 Ω·m, about 65 times higher.
  • Length - twice as long, twice the resistance (twice as many collisions).
  • Cross-section area - twice as thick, half the resistance (twice as many paths side by side).
  • Temperature - metals resist more when hot (a lamp filament is about 10× higher hot than cold).
R = ρ × L / A
R
resistance (Ω)
ρ
resistivity of the material (Ω·m)
L
length (m)
A
cross-section area (m²); 1 mm² = 1 × 10−6 m²
Worked example: a 10 m cable

What is the resistance of 10 m of 1.5 mm² copper wire (common house wiring for lights)?

  1. A = 1.5 mm² = 1.5 × 10−6 m².
  2. R = 1.68 × 10−8 × 10 / 1.5 × 10−6.
  3. R = 0.112 Ω.

Answer: 0.112 Ω - tiny, but not zero. A current must go there AND back, so a 10 m run has 20 m of wire in the loop: 0.224 Ω. You will see in the next section why that matters for solar systems.

Resistors: resistance on purpose

A resistor is a part made to have a known resistance - 220 Ω, 10 kΩ (10 000 Ω), 1 MΩ (1 000 000 Ω). Resistors limit current (so an LED does not burn), set voltages (the voltage divider) and turn current into a voltage that a microcontroller can read. They are the most common part on any circuit board.

Open circuits and short circuits

An open circuit is a break in the loop: a switch that is off, a broken wire, a blown fuse, a cracked solder joint. Its resistance is (almost) infinite and no current flows anywhere in that loop.

A short circuit is the opposite: a path of (almost) zero resistance where there should not be one, so the current takes the easy path. With nothing to limit it, the current becomes enormous - only the battery's own resistance and the wires hold it back. Wires overheat, insulation melts, batteries can burst.

A short circuit: the wire on the right is in parallel with the lamp and has almost no resistance. Nearly all the current goes through it - the lamp goes out and the battery is shorted.
A short circuit: the wire on the right is in parallel with the lamp and has almost no resistance. Nearly all the current goes through it - the lamp goes out and the battery is shorted.

Where you meet it

Cable sizing

Long runs (solar panels on the roof, a borehole pump at the end of the garden) need thicker cable so the wire's resistance stays small.

Heating elements

Kettles, irons and water heaters use high-resistance nichrome wire so the current turns into heat.

Fault finding

"Nothing works" is usually an open circuit (a broken wire, a blown fuse); "it blew the fuse" is usually a short.

Practice 1What is the resistance of 100 m of 2.5 mm² copper cable?

Hint

R = ρ L / A with ρ = 1.68 × 10−8 Ω·m and A = 2.5 × 10−6 m².

Show the answer

Answer: 0.672 Ω

R = 1.68 × 10−8 × 100 / 2.5 × 10−6 = 0.672 Ω.

Practice 2You double a wire's length AND double its cross-section area. Its resistance:

  1. doubles
  2. halves
  3. stays the same
  4. becomes four times bigger
Show the answer

Answer: C. stays the same

Double the length doubles R, double the area halves it: the two cancel.

Practice 3A torch does not light. The bulb is good and the battery is new. The most likely fault is:

  1. A short circuit
  2. An open circuit - a bad contact or a broken wire
  3. Too much current
  4. The resistance is too low
Show the answer

Answer: B. An open circuit - a bad contact or a broken wire

Nothing flows: the loop is broken somewhere. A short would usually flatten the battery or make it hot.

Challenge 410 m of 1.5 mm² copper has a resistance of 0.112 Ω. Without using ρ, what is the resistance of 25 m of 2.5 mm² copper?

Hint

Scale by the length ratio, then by the inverse of the area ratio.

Show the answer

Answer: 0.168 Ω

Length × 2.5 → 0.28 Ω. Area × (2.5 / 1.5) → divide by 1.667: 0.28 / 1.667 = 0.168 Ω.